A family car has a mass of 1400 kg. In an accident it hits a wall and goes from a speed of 27 m/s to a standstill in 1.5 seconds. By how much would the force have been reduced if the car had had a crumple zone that increased the collision time to 2.2 seconds? Give your answer to the nearest whole number.

The amount of force which is reduced is required.

The force would be reduced by 8018.18 N.

m = Mass of car = 1400 kg

u = Initial velocity = 27 m/s

v = Final velocity = 0 m/s

= Initial time = 1.5 s

= Final time = 2.2 s

Force is given by

The difference in force will be

The force would be reduced by 8018.18 N.

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The force has been reduced by 8018 N

Explanation:

The impulse exerted on the car during the crash is equal to the product of the force exerted and the duration of the collision, and it is also equal to the change in momentum of the car. So we can write:

where:

F is the force exerted on the car

is the duration of the collision

m = 1400 kg is the mass of the car

is the change in velocity of the car

We can re-write the equation as

In the 1st collision, the time is 1.5 seconds, so the force is

In the 2nd collision, the time is increased to 2.2 seconds, so the force is

Therefore, the force has been reduced by:

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000

there are no contact forces mentioned on the list of choices that you've provided.