An object traveling westward with an initial velocity of 11.2 m/s experiences a constant acceleration of 2.78 m/s^2 2 in the eastward direction for 2.03 seconds. During this time, the object travels a distance of:

Explanation:

Given that,

The initial velocity of the object, u = -11.2 m/s (due west)

Acceleration of the object, (due east)

Time, t = 2.03 seconds

We need to find the distance traveled by the object during this time. Let the distance covered is d. Using second equation of motion to find it as :

So, the object cover a distance of 17.007 meters in the westward direction.

your answer is, orbit around the nucleus

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y