For a submarine, identify when it will have the GREATEST buoyant force acting on it. Assume that neither the volume of the submarine nor the density of the water change. Choose all that apply.

a. When it is empty and fully submerged at a depth of 89 m.
b. When it is empty, fully submerged, and resting on the bottom at a depth of 178 m.
c. When it is in dry dock and no part of it is submerged in water.
d. When it is full of cargo and floating on the surface.
e. When it is empty and floating on the surface.
f. When it is full of cargo, fully submerged and resting on bottom at a depth of 178 m.
g. When it is full of cargo and fully submerged at a depth of 89 m.

a, c, and g

Explanation:

Buoyant Force is an upward force acting on submerged object equal to weight of fluid displaced by the submerged object.

If no part is submerged (V = 0) that is volume. Therefore there is Zero Buoyant Force.

Fully submerged produces greatest buoyant force since greatest amount of fluid was displaced.

Whenever it is fully submerged it will have the greatest buoyant force.

Buoyant Force DOES NOT Depend on Depth

A fully submerged object displaces its volume in fluid

A floating object displaces its weight in fluid.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂