2. A cylinder/piston arrangement contains water at 105ºC, 85% quality, with a volume of 1 L. The system is heated, causing the piston to rise and encounter a linear spring. At this point the volume is 1.5 L, the piston diameter is 150 mm, and the spring constant is 100 N/mm. The heating continues, so the piston compresses the spring. What is the cylinder temperature when the pressure reaches 200 kPa?

Explanation:

The given data is as follows.

      ,     x = 0.85

        = 1 L = 0.001   (as 1 L = 0.1 )  

      = 1.5 L = 0.0015 ,

      = 150 mm = 0.15 m,     K = 100 N/mm = 100 kN/m

      = 200 kPa

According to the table,

      = 120.8 kPa,     = 0.001047 m/kg

So, we have

                    = 0.001047 + 0.85 \times (1.41831 m^{3}/kg)" alt="m^{3}/kg" />

So, we have

                    = 0.001047 + 0.85 \times (1.41831 m^{3}/kg)" />    

                    = 1.2066

Now, we will calculate as follows.

                   =

                   = 0.000828 kg

Now,  Area =

                   =

                   = 0.0176

As we have,

                       =

                       = 1.8099

From table, for = 120.8 kPa and .

    200 =

Therefore, from the table

               T = ,      v = 2.01297

               T = ,     v = 2.2443

                =

Thus, we can conclude that the cylinder temperature when the pressure reaches 200 kPa is .

the average speed is 24.57 km/hr

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it