A long solenoid has a length of 0.54 m and contains 1900 turns of wire. There is a current of 2.5 A in the wire. What is the magnitude of the magnetic field within the solenoid?

Therefore,

Strength magnetic field at within the Solenoid,

Explanation:

Given:

Turn = N = 1900

length of solenoid = l = 0.54 m

Current, I = 2.5 A

To Find:

Strength magnetic field within the Solenoid,

B = ?

Solution:

If N is the number of turns in the length, the total current through the rectangle is NI. Therefore, Ampere’s law applied to this path gives

Where,

B = Strength of magnetic field

l = Length of solenoid

N = Number of turns

I = Current

Therefore,

Substituting the values we get

Therefore,

Strength magnetic field at within the Solenoid,

the moving of the box is a result of centripetal force. think of that  as a car or a truck in this case creates a turn, the force of friction performing upon the turned wheels of the car runs centripetal force obligatory for circular motion for the things inside it.

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