Hearing the siren of an approaching fire truck, you pull over to the side of the road and stop. As the truck approaches, you hear a tone of 470 Hz ; as the truck recedes, you hear a tone of 400 Hz .Howmuch time will it take for the truck to get from your position to the fire 5.0 km away, assuming it maintainsa constant speed?

time = 182.68 s

Explanation:

given data

truck approaches = 470 Hz

truck recedes =  400 Hz

position away =  5.0 km

solution

if V is the speed of sound in air and v is the speed to truck

f is the frequency of sound

when truck approach

f1 =  

and when truck recede

f2 =  

so here we can say

  ...........1

v = 27.37 m/s

so here 5 km

S = u×t  + 0.5 ×a×t²  ...........2

5 × 10³ = 27.37 t + 0

t = 182.68 s

are you like autistic or something?

xd

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j