The distance between two telephone poles is 50 m. A 1 kg bird lands on the telephone wire midway between the poles, and the wire sags 0.2 m. How much tension does the bird produce in the wire

the tension produce by the bird in the wire is 610.3 N.

Explanation:

given information:

mass of the bird, m = 1 kg

distance of two telephone pole, L = 50 m

wire sag, y = 0.2

the tension of the wire can be calculate by the following equation

tan θ = y/(L/2)

         = 0.2/(50/2)

         = 0.2/25

thus

θ = arc tan (0.2/25)

  = 0.46°

according to Newton's first law

ΣF = 0, vertical direction

T sin θ + T sin θ - mg = 0

2 T sin θ = m g

T = mg/2 sinθ

  = 1 x 9.8/(2 sin 0.46)

  = 610.3 N

what are the options.

explanation: