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A bowling ball is launched off the top of a 240-foot tall building. The height of the bowling ball above the ground t seconds after being launched is s(t) = −16t 2 + 32t+ 240 feet above the ground. What is the velocity of the ball as it hits the ground?
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A bowling ball is launched off the top of a 240-foot tall building. The height of the bowling ball a...
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