Calculate the force that must be exerted on the master cylinder of a hydraulic system to lift a 10,000 kg truck with the slave cylinder. The master cylinder has a diameter of 1.50 cm and the slave has a diameter of 30.0 cm.

245N

Explanation:

pressure =

Force = mg

g=9.8m/s²

Area = πd²/4

Assuming the pressure across the hydraulic system is constant, then;

=

F₁ = Force on master cylinder

A₁ = Area of master cylinder

F₂ = Force on slave cylinder

A₂ = Area of slave cylinder

F₂ = mg

=10000 × 9.8

= 98000N

A₂ = πd² / 4

=π30²/4

=π900/4

=225π

A₁ = πd²/4

=π1.5²/4

=π2.25/4

=π0.562

recall, =

=

= 0.5625 × 98000 / 225π

F₁ = 0.0025 × 98000

=245N

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the keisha 's machine labels are

x : load

y: fulcrum

z: lever