You cool a 130.0 g slug of red-hot iron (temperature 745 ∘C) by dropping it into an insulated cup of negligible mass containing 85.0 g of water at 20.0 ∘C. Assume no heat exchange with the surroundings. How do you do this?
Part A What is the final temperature of the water?
Part B What is the final mass of the iron and the remaining water?
Answers: 1
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