A slab of glass with an index of refraction of 1.65 is submerged in a liquid with an index of refraction of 1.22. Light in the liquid is incident on the glass.
(a) Find the angle of refraction for the angle of incidence of 60°.
°

(b) Find the angle of refraction for the angle of incidence of 45°.
°

(c) Find the angle of refraction for the angle of incidence of 30°.

Explanation:

Given that,

Refractive index of glass, n₁ = 1.65

Refractive index of liquid, n₂ = 1.22

(a) We need to find the angle of refraction for the angle of incidence of 60°. It can be calculated using Snells law as :

r is the angle of refraction

(b)

r is the angle of refraction

Here, i = 45 degrees

(c)  

r is the angle of refraction

Here, i = 30 degrees

Hence, this is the required solution.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

i guess it’s a and b