An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.80 mm. If a 17.0 V potential difference is applied to these plates, calculate the following: ](a) the electric field between the plateskV/m(b) the capacitancepF(c) the charge on each platepC

(a) E=9.44×10³ V/m

(b) C=3.74pF

(c) Q=63.6pF

Explanation:

For Part (a)

The electric field between the plates is found by:

E=ΔV/d

Substitute  the given values

So:

For Part (b)

The capacitance of parallel plate capacitor found from:

C=(∈₀A)/d

Substitute the given values

For Part (c)

The Charge on each plate of capacitor is found by:

Q=CΔV

Substitute the  given values

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.

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