Four resistors of 12, 3.0, 5.0, and 4.0 Ω are connected in parallel. A 12-V battery is connected to the combination. What is the current through the battery?

Therefore,

The current through the battery is 10.4 Ampere.

Explanation:

Given:

V = 12 V  Battery

Connection is Parallel,

R₁ = 12 Ω

R₂ = 3 Ω

R₃ = 5 Ω

R₄ = 4 Ω

Let I₁, I₂, I₃, I₄ be the current passing through R₁ ,R₂, R₃, R₄  resistors

To Find:

I =? (current through the battery)

Solution:

As Connection is Parallel Voltage Remain SAME through resistors

Bu Ohm's Law we have

So current through R₁

Substituting the values we get

Similarly, for current through R₂, R₃, R₄,

Now in Parallel Connection we have,

Substituting the values we get

Therefore,

The current through the battery is 10.4 Ampere.

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.