The frequency of the harmonics following a fairly simple pattern, as described in the text. If the frequency of the fundamental (n=1) harmonic is 70.0 Hz, what is the frequency of the second harmonic(n=2)?

f2 = 140 Hz

Explanation:

let fundamental frequency is f1 = 70.0 Hz

formula for finding the higher frequency when fundamental frequency is known

fn = n f1          (where f1 is fundamental frequency and n = 1,2,3,4,5)

for the second frequency n=2

f2 = 2 × 70.0 Hz

f2 = 140 Hz

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

b.

explanation: