It takes 101 J of work to move 2 C of charge from the negative plate to the positive plate of a parallel plate capacitor. What voltage difference exists between the plates

10.05volts

Explanation:

Work done to move a charge from the positive side of a plate to the negative side is represented mathematically as 1/2CV² which is also the energy stored by the capacitor.

Work done = 1/2CV² where

C is the charge

V is voltage difference that exists between the plates.

Given Work done = 101Joules

C = 2Coulombs

Substituting the values in the formula to get V, we will have;

101 = 1/2(2)V²

101 = V²

V = √101

V = 10.05volts

Therefore the voltage difference between the plates is 10.05colt's

you have to draw the persons position over there

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be