A Nichrome heater dissipates 526 W when the applied potential difference is 110 V and the wire temperature is 800oC. What would be the dissipation rate if the wire temperature were held at 200oC by immersing the wire in a bath of cooling oil? The applied potential difference remains the same, and α for Nichrome at 800oC is 4.0 × 10-4 K-1.

i already answered it by 34/s

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m

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