During an occultation, or "covering up," of Jupiter by the Moon, an astronomer notices that it takes the Moon’s edge 90 seconds to cover Jupiter’s disk completely (starting from the moment of initial "contact"). If the Moon’s motion is assumed to be uniform and the occultation was "central" (that is, center over center), find the angular diameter of Jupiter. Express your answer in arcseconds. [Hint: Assume that Jupiter does not appear to move against the background of stars during this brief 90-second interval. You will need to convert the Moon’s angular speed from degrees per day to arcseconds per second.]