A bird sits on a high-voltage power line with its feet 5.000 cm apart. The wire is made from aluminum, is 2.00 cm in diameter, and carries a current of 170.0 A. What is the potential difference between the bird's feet?

The potential difference between the bird's feet is 0.71 mV

Explanation:

Given-

Distance between the feet, x = 5 cm = 0.05 m

Diameter of the wire = 2 cm

Radius, r = 2/2 = 1 cm = 0.01 m

Current, I = 170 A

Potential difference, ΔV = ?

We know,

ΔV = IR

Where,

ΔV is the potential difference

I is the current

R is the resistance of the wire

And also

R = ρ L/ A

where,

ρ is the resistivity of aluminium wire (ρ = 2.65 X 10⁻⁸ Ωm)

L is the length

A is the area

Equating both the equations,

ΔV = I * ρL/A               (The value of R is replaced in the first equation)

ΔV =

Therefore, the potential difference between the bird's feet is 0.71 mV

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