A spaceship of proper length ? = 100 m travels in the positive x direction at a speed of 0.700 c0 relative to Earth. An identical spaceship travels in the negative x direction along a parallel course at the same speed relative to Earth. At t = 0, an observer on Earth measures a distance d = 58,000 km separating the two ships.

Part A

At what instant does this observer see the leading edges of the two ships pass each other?

The time at which the observer see the leading edges of the two ships pass each other is 0.138 sec.

Explanation:

Given that,

Length = 100 m

Speed = 0.700 c

Distance = 58000 km

The distance should be halved because the spaceships both travel the same speed.

So they will meet at the middle of the distance

We need to calculate the distance

Using formula for distance

Put the value into the formula

We need to calculate the time at which the observer see the leading edges of the two ships pass each other

Using formula of time

Put the value into the formula

Hence, The time at which the observer see the leading edges of the two ships pass each other is 0.138 sec.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)