A liquid with a mass of 75 g is at its boiling point. It completely boils off when AQ = 15000000) of heat energy is added to it. Calculate the substance's latent heat of vaporization.
Temperature
Specific Heat
Latent Heat of
la
C - Celsius Temp (°C)

2 × 10⁸J/kg

Explanation:

Specific latent heat of vaporization (steam)  is the quantity of heat required or needed to change a unit of mass of liquid to gaseous state at constant temperature (boiling point) and pressure.

It can be calculated mathematically using,

Q = mL

Where,  Q = quantity of heat

m= mass in kg

L = specific latent heat (J/kg)

Therefore,from the question

Q= 15000000J

mass (m)  = 75g = 75/1000 kg = 0.075kg

Q = mL

L = Q/m

L = 15000000  ÷ 0.075

L= 200000000J/kg

L = 2 × 10⁸J/kg

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magnified images possible images can be real = projected onto a screen

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form