A satellite is in a circular orbit very close to the surface of a spherical planet. The period of the orbit is 2.17 hours. What is density of the planet

Explanation:

Lets consider

Circumference of orbit = T

as it is mentioned in the question that a satellite is in orbit that is very close to the surface of planet. so

circumference of orbit = circumference of planet

Time period = T

radius of planet = R

orbital velocity = V

gravitational constant = G

mass of planet = m

Solution:

Time period for a uniform circular motion of orbit is,

T =

where p = density

T = 2.17 hours = 7812 sec

(7812)² = [( 3×3.14)/6.67××ρ)]

ρ = 6.28/6.67××6.10×

ρ = 6.28/40.687×

ρ = 0.1543×kg/m³

ρ = 15.43×kg/m³

b. latent learning (the word "latent" itself means something that exists but isn't obvious, only under certain conditions! )

15.3 cos 65 degrees trig