A constant force of 30 N pulls on a 16 kg block on a horizontal surface. The force is directed at 37 degree above the horizontal. A friction force impedes the motion. a. What is the work done by the constant force when the block is moved 10 meters? b. If at the start of the motion the block was at rest and after 10 meters it has velocity of magnitude |v| = 3 m/s, what is the coefficient of friction?

(a).The work done by the constant force is 239.5 J.

(b). The coefficient of friction is 0.12

Explanation:

Given that,

Force = 30 N

Mass of block = 16 kg

Angle = 37°

Distance = 10 m

Velocity = 3 m/s

(a). We need to calculate the work done by the constant force

Using formula of work done

Put the value into the formula

(b). If at the start of the motion the block was at rest and after 10 meters it has velocity of magnitude |v| = 3 m/s,

We need to calculate the acceleration

Using equation of motion

Put the value into the formula

We need to calculate the coefficient of friction

Using formula of frictional force

...(I)

Here, normal force is

Net force is

Put the value of N in equation (I)

Put the value into the formula

Hence, (a).The work done by the constant force is 239.5 J.

(b). The coefficient of friction is 0.12

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