Albert pushes a 6 kg box across a level floor. He pushes with a force of 43 N and observes that the box accelerates in the direction of his push at a rate of 2 m / s 2 . What is the net force acting on the box

12 N

Explanation: according to Newton second law of motion,

F - Fr = ma.

Where F = applied force = 43 N, Fr = frictional force =?, m = mass of box = 6kg, a = acceleration = 2m/s²

43 - Fr = 6(2)

43 - Fr = 12

Fr = 43 - 12

Fr = 31 N

If applied force (F) is 43 N and the frictional force (Fr) is 31 N The resultant forge is 43 - 31 = 12 N

f=ma newton

f=100x2.5=250n