During a practice shot put throw, the 7.7-kg shot left world champion C. J. Hunter's hand at speed 14 m/s. While making the throw, his hand pushed the shot a distance of 1.4 m. Assume the acceleration was constant during the throw. A) Determine the acceleration of the shot.
B) Determine the time it takes to accelerate the shot.
C) Determine the horizontal component of the force exerted on the shot by hand.

answer: good job it's all correct !

explanation:

f=ma newton

f=100x2.5=250n

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft