The same potential difference is applied across two wires. Wire A carries twice thecurrent of wire B. If the resistance of wire B isR, what is the resistance of wire A?

R / 2

Explanation:

According to Ohm law, the current flowing within the resistor is the ratio between the potential difference and the resistance:

So if wire A carries twice the current of wire B, while their potential is the same then:

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j