Answers: 3
![W=3.024[J]](/tpl/images/0530/0553/e11eb.png)
(1) ![A=\pi (D/2)^{2}[\tex]=0.20 cm^{2})ΔL is the amount by which the length of the object changes (ΔL=12 cm)L(0) is the initial length (L(0) = 10 m = 1000 cm)We just need to put it in the equation (1):[tex]W=\frac{1}{2}\frac{21000*0.20*12^{2}}{1000}=302.4 [N*cm]](/tpl/images/0530/0553/2a760.png)
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A steel rod of 0.5 cm diameter and 10 m length is stretched 12 cm. Young’s modulus for this steel is...
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