The elevator of a large building is to raise a net mass of 600 kg at a constant speed of 12 m/s using an electric motor. What is the minimum power rating of the motor?

Explanation:

Given that.

Mass=600kg

v=12m/s

Since it is moving up then gravity is acting on it

take g=9.8m/s²

Then,

Power=workdone/time

Work done=force ×distance

Power=force×distance/time

Then, velocity =distance/time

So,

Power=force ×velocity.

The force to raise the object up is the weight of the object

Force=weight=mass ×gravity

Power=mass×gravity ×velocity.

Power=600×9.8×12

Power, =70560watts

Power=70.56KW

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it