Answers: 3
Physics, 21.06.2019 13:30, paulitaaustin
An astronomer at the equator measures the doppler shift of sunlight at sunset. from this, she calculates that earth’s tangential velocity at the equator is 465 m/s. the centripetal acceleration at the equator is 3.41 10 2 m/s 2 . use this data to calculate earth’s radius.
Answers: 3
Physics, 21.06.2019 23:30, aprilwilson3p8711m
Truck traveling west on the highway experiences an acceleration to the east. what could be the cause of this acceleration
Answers: 1
Physics, 22.06.2019 01:10, twhalon72
The x-coordinate of a particle in curvilinear motion is given by x = 3.1t3 - 4.9t where x is in feet and t is in seconds. the y-component of acceleration in feet per second squared is given by ay = 2.3t. if the particle has y-components y = 0 and vy = 5.0 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 1.8 sec. sketch the path for the first 1.8 seconds of motion, and show the velocity and acceleration vectors for t = 1.8 sec. answers: v = ft/sec a = ft/sec2
Answers: 2
If we increase the amount of work, and all other factors remain the same, the amount of power will?...
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