Physics, 29.02.2020 03:44 raizagisselle1694
A potential difference V is applied to a wire of cross-section area A, length ℓ, and conductivity σ. You want to change the applied potential difference and add length to the wire so that the power dissipated is increased by a factor of 30 and the current is increased by a factor of 4. Let the wire have the same cross-sectional area before and after it is lengthened. What is the ratio of the new length to the original length?
Answers: 2
.
and 
and new length be 
.
equation 1. ( Since , cross section area is same )
equation 2.
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A potential difference V is applied to a wire of cross-section area A, length ℓ, and conductivity σ....
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