Now the friends attempt to use their knowledge to work a problem. A heater is rated at 1600 W at a potential difference of 120 V. What is the current though the nichrome wire of the heater when it is turned on? 13.5 Correct: Your answer is correct. A What is the resistance in the wire? 12 Incorrect: Your answer is incorrect. Your response differs from the correct answer by more than 10%. Double check your calculations. Ω

I = 13.33 A

R=9.002  Ω

Explanation:

Given that

Power ,P = 1600 W

Potential difference ,ΔV = 120 V

Lets take current = I

We know that power P is given as

P = V I

I=Current

ΔV =Voltage difference

P=Power

Now by putting the values in above equation

1600 = 120 x I

I = 13.33 A

Therefore the current will be 13.33 A.

We know that

ΔV = I R

R=Resistance

I=Current

ΔV =Voltage difference

Now by putting the values in above equation

120 = 13.33 x R

R=9.002  Ω

Therefore the resistance will be 9.002  Ω

6/12=1/2

step-by-step explanation: