A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0.90 m/s each second. The push force has a horizontal component of 20 N and a vertical component of 25 N downward.

The given question is incomplete. The complete question is as follows.

A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0.90 m/s each second. The push force has a horizontal component of 20 N and a vertical component of 25 N downward. Calculate the coefficient of kinetic friction between the box and the floor.

Explanation:

The given data is as follows.

    = 20 N, = 25 N, a = -0.9

             W = 83 N

         m =

             = 8.46

Now, we will balance the forces along the y-component as follows.

       N = W +

           = 83 + 25 = 108 N

Now, balancing the forces along the x component as follows.

        = ma

              = 7.614 N

Also, we know that relation between force and coefficient of friction is as follows.

                    =

                    = 0.0705

Thus, we can conclude that the coefficient of kinetic friction between the box and the floor is 0.0705.