Describe, in detail, an experiment in which you could determine the power for a period of several hours. You must be able to tell how to measure the force and the distance to calculate work or your example will not be accepted.

Explanation:

Fill up the tank of water which is at a height.

So Work Done = Change n Potential Energy = mgh

Here h is the Height of the Center of mass of the water

Divide it by Time to get power

Lets say, we have a car with a specific mass, m and is forced to move in given direction starting from its initial point "A", to a final position "B". The force,F which makes it move in that direction is about 10 N in total. While, the distance,D covered between the two given points is about 5 meters. So, now we can calculate the work,W done by the car in a given direction inside that specific area. So, we have to place all the values inside the equation mentioned below,

So, after placing the required data into the equation, we will get the following results:

W=(10)*(5),

However, to find out the power dissipation,P for a system which runs on a given scale of time,t as the current,I and the potential difference or voltage,V is all involved to find out the total power dissipation inside the circuit or any system that is under consideration. Lets, say we have circuit in which a charge of 6 coulombs(C) passes through a wire of certain length,L. And that the given time is about 2 seconds(sec). The voltage,V provided to the circuit is about 7 volts(V), so how can we be able to find the amount of power dissipation inside the circuit.

So, for that reason we have the following equation, which is given as follows:

P=I.V,

And we can also evaluate the equation much further, as follows:

P=(Q/t).(v), ∴I=Q/t,

So, we can have the required results that we desire by placing the data inside the equation:

P= (6/2)*(7),

P=3*7,

force tends to be low and long diustance masses are high

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft