A tissue sample at 275 K is submerged in 2 kg of liquid nitrogen at 70 K for cryopreservation. The final temperature of the nitrogen is 75 K. What is the heat capacity of the sample in J/K? (Note: Assume no heat is lost to the surrounding air.) A.0.05 J/K

37.8 J/k

Explanation:

Temperature =T=275 K

Mass of liquid nitrogen=2 kg

Initial temperature=

Final temperature=

We have to find the heat capacity of the sample in J/K.

Specific heat of liquid nitrogen=

We know that

Using the formula

Hence, the heat capacity of sample=37.8 J/k

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