To move a refrigerator of mass 170 kg into a house, a mover puts it on a dolly and covers the steps leading into the house with a wooden plank acting as a ramp. The plank is 9.6 m long and rises 3.3 m. The mover pulls the dolly with constant velocity and with a steady force 1400 N up the ramp. How much work does he perform? The acceleration of gravity is 9.8 m/s 2 . Answer in units of J.

Explanation:

The given data is as follows.

         mass (m) = 170 kg,        Distance (s) = 9.6 m

        Height (h) = 3.3 m,         Force (F) = 1400 N

First, we will calculate the work performed by her as follows.

                W = Fs

                    =

                    = 13440 J

Hence, minimal work necessary to lift the refrigerator is as follows.

               U = mgh

                   =

                   = 5497.8 J

Therefore, we can conclude that he performed 5497.8 J of work.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y