In a wire with a 1.35 1.35 mm2 cross-sectional area, 5.41 × 10 20 5.41×1020 electrons flow past any point during 2.19 2.19 s. What is the current in the wire?

The current in the wire = 39.53 A.

Explanation:

The given cross -sectional area of the wire  = 1.35 .

The number of electrons flowing in the wire at any point is  

= 5.41 electrons.

The charge of an electron is known to be  =

The electronics flow across the wire for a time of, t = 2.19 seconds.

The current in the wire  = (number of electrons) ×

                                       = 5.41 ×

                                       =  39.53 A.

The formula for current is actually, i =  .  

The (number of electrons )×(charge of an electron) will equal the total charge flowing through the wire in the given time  = 2.19 seconds.

The current in the wire = 39.53 A.

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.