A person applies a 13.5 N force to a hammer while it moves a distance of .12 m. The hammer completes 1.56 J of work on the nail. What is the efficiency of the hammer? Must show all work, have correct sig figs, and include correct units for full credit

The efficiency of the hammer is 96.29%

Explanation:

Given-

Force, F = 13.5N

Distance, x = 0.12m

Work, W1 = 1.56J

Efficiency, η = ?

Work done = F X x

W2 = 13.5 X 0.12J

W2 = 1.62J

Efficiency = W1 / W2 X 100

η = 1.56/1.62 X 100

η = 96.29%

Therefore, the efficiency of the hammer is 96.29%

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