The vapor pressures of pure carbon disulfide and carbon tetrachloride are 360 and 99.8 torr, respectively, at 296 K. What is the vapor pressure of a solution containing 50.0 g of each compound

273.84 Torr

Given

Carbon disulfide = CS2

Carbon tetrachloride = CCL4

CS2 Partial Pressure = 360 Torr

CCL4 Partial Pressure = 99.8 Torr

Grams of CS2 and CCL4 = 50g each

Molar Mass of CS2 = 76.139 g/mol

Molar Mass of CCL4 = 153.82 g/mol

Calculating Moles of both substance...

The molar fraction is calculated by dividing the grams by the molar mass to get moles of each substance

Moles of CS2 = 50g/76.139g/mol

= 0.6567 mol

Moles of CCL4 = 50g/153.82g/mol

= 0.3251 mol

Total = 0.6567 + 0.3251 = 0.9818

Then, we find the Mole fraction of each substance.

Mole Fraction of CS2 = 0.6567/0.9818

= 0.6689

Mole fraction CCL4 = 0.3251/0.9818

= 0.3311

Vapour Pressure of Solution is calculated by

Mole fraction CS2 * Partial pressure CS2 +Mole fraction CCL4 * Partial pressure CCL4

Vapour Pressure = 0.6689 * 360 + 0.3311 * 99.8

= 240.80 + 33.04

= 273.84 Torr

= atm

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.