What is the electric potential at the point on the x-axis where the electric field is zero?

the closer the planet is to the sun, the larger the gravity

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

answer( sicar );