A bird is flying in a circle of radius 50m at a constant speed of 5 m/s. The bird is flying clockwise, as seen from above. at the moment when the bird is flying north, what is the magnitude and direction of the bird's acceleration?

0.5 m/s² clockwise

Explanation:

Acceleration: This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s².

The acceleration of a body undergoing circular motion is given as,

a = v²/r Equation 1

Where a = acceleration of the bird, v= velocity of the bird, r = radius of the circle.

Given: v = 5 m/s, r = 50 m.

substitute into equation 1

a = 5²/50

a = 25/50

a = 0.5 m/s².

Hence the acceleration of the bird = 0.5 m/s² clockwise

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west