Given that the dipole moment (μ) of the HF molecule is 1.82 Debye and the bond length on an HF molecule is 0.92 Å, what is the magnitude of the charge (in Coulombs, C) of the partial positive and partial negative charges in an HF molecule?

Magnitude of charge, q of HF is 6.58 X 10⁻²⁰ C

Explanation:

Dipole moment, μ = 1.82 Debye

1 Debye = 3.33 X 10⁻³⁰ Cm

μ = 1.82 X 3.33 X 10⁻³⁰ Cm

μ = 6.06 X 10⁻³⁰ Cm

Bond length, x = 0.92Å = 0.92 X 10⁻¹⁰m

Charge, q = ?

We know,

Dipole moment, μ = charge X Bond length

6.06 X 10⁻³⁰ Cm = q X 0.92 X 10⁻¹⁰m

q = 6.58 X 10⁻²⁰ C

Therefore, magnitude of charge, q of HF is 6.58 X 10⁻²⁰ C

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explanation: