Suppose you push a hockey puck of mass m across frictionless ice for a time \Delta t, starting from rest, giving thepuck speed v after traveling distance d. If you repeat the experiment with a puck of mass2m,

1. How long will you have to push for the puck to reach the samespeed v?
t/ (delta t) = ?
2.How long will you have to push for the puck to travel the samedistance d?
t/ (delta t) = ?

1.

2.

Explanation:

1. According to Newton's law of motion, the puck motion is affected by the acceleration, which is generated by the push force F.

In Newton's 2nd law: F = ma

where m is the mass of the object and a is the resulted acceleration. So in the 2nd experiment, if we double the mass, a would be reduced by half.

Since the puck start from rest, in the 1st experiment, to achieve speed of v it would take t time

Now that acceleration is halved:

You would need to push for twice amount of time

2. The distance traveled by the puck is as the following equation:

So if the acceleration is halved while maintaining the same d:

As , then . Also

So t increased by 1.14

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge