A positive charge of 18nC is evenly distributed along a straight rod of length 4.0 m that is bent into a circular arc with a radius of 2.0 m. Find the magnitude of the electric eld at the center of curvature of the arc

Explanation:

Formula for angle subtended at the center of the circular arc is as follows.

where,   S = length of the rod

              r = radius

Putting the given values into the above formula as follows.      

                             =

                             =

                             =

Now, we will calculate the charge density as follows.

                            =

                            =

Now, at the center of arc we will calculate the electric field as follows.

                 E =

                     =

                      = 34.08 N/C

Thus, we can conclude that the magnitude of the electric eld at the center of curvature of the arc is 34.08 N/C.

answer would be d.) i hope this

explanation: