The distance between neighboring singly charged sodium and chlorine ions in crystals of table salt (NaCl) is 2.82*10^-10m.

What is the attractive electric force between the ions?

2.897×10⁻⁹ N.

Explanation:

From coulomb's law,

F = kqq'/r² Equation 1

Where F = attractive force between the ions, q = charge on sodium ion, q' = charge on chlorine ion, r = distance between sodium and chlorine ion, k = coulomb's constant

Given:q = 11×1.6×10⁻¹⁹ C, q' =17×1.6×10⁻¹⁹ C, r = 2.82×10⁻¹⁰ m, k = 9×10⁹ Nm²/C²

Substitute into equation 1

F = 9×10⁹ (1.6×10⁻¹⁹ )(1.6×10⁻¹⁹ )/(2.82×10⁻¹⁰ )²

F = 23.04×10⁹ (2.56×10⁻³⁸)/(7.9524×10⁻²⁰)

F =(23.04×10⁻²⁹)/(7.9524×10⁻²⁰)

F =  2.897×10⁻⁹ N.

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