A cannonball is launched horizontally off a 80 m high castle wall with a speed of 25 m/s. How long will the cannonball be in flight before striking the ground

The cannonball will be spend 4.04 seconds before striking the ground.

Explanation:

Given:

vertical height = 80 m

horizontal velocity = 25m/s

Initial vertical velocity, Vy= 0

Applying equations of motion;

s = Vy*t + ¹/₂gt²

80 = ¹/₂*9.8t²

4.9t² = 80

t² = 80/4.9

t² = 16.327

Therefore, the cannonball will be spend 4.04 seconds before striking the ground.

2.23 s.

Explanation:

Given:

S = 80 m

voy = 0 m/s

vox = 25 m/s

g = 9.81 m/s^2

Using equation of motion,

S = vo*t + 1/2 * g * t^2

80 = 0 + 4.905t^2

Solving this equation, we have:

t = sqrt(16.31)

= 4.039 s

Therefore, t = 4.04 s.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)