A geosynchronous satellite orbits Earth at a distance of 42,250 km from the center of Earth and has a period of 1 day. What is the centripetal acceleration of the satellite (in m/s2)?

The centripetal acceleration of the satellite is .

Explanation:

Given that,

The distance covered by a geosynchronous satellite, d = 42250 km

The time taken by the satellite to covered distance, t = 1 day = 24 hours

Since, 24 hours = 86400 seconds

Let v is the speed of the satellite. It is given by the total distance divided by total time taken such that :

v = 3072.5 m/s

The centripetal acceleration of the satellite is given by :

So, the centripetal acceleration of the satellite is . Hence, this is the required solution.

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explanation:

double the distance = divide strength by 4