Two stationary point charges +3.00 nC and +2.00 nC are separated by a distance of 50.0 cm. An electron is released from rest at a point midway between the two charges and moves along the line connecting the two charges. What is the speed of the electron when it is 10.0 cm from the +3.00-nC charge?

Explanation:

Point charge =

Separation by distance = s = 50.0 cm = 0.5 m   (as 1 m = 100 cm)

Electric potential energy of electron at 0.10 m =

Electric potential energy of electron at 0.10 m = J

Change in P.E. will be calculated as follows.

                P.E =

                 K.E =

Therefore, we will calculate the speed as follows.

         Speed (v) =

                v =

                  = m/s

when electron is 10.0 cm from the +3.00 nC charge then its speed is m/s.

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.