Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon's tongue accelerates at a remarkable 280 m/s^2 for 20 ms, then travels at constant speed for another 30 ms.

During this total time of 50 ms 1/20 of a second, how far does the tongue reach?

Express your answer to two significant figures and include the appropriate units.

0.224 m

Explanation:

The motion of the first 20 ms is a uniformly accelerated motion. With an initial velocity of 0 m/s, the equation of motion used is

where is the distance, is the initial velocity, is the acceleration and is the time.

The velocity, , at the end of this part of the motion is

.

This velocity is maintained for 30 ms through a distance of

The total distance is 0.056 + 0.168 = 0.224 m

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