Physics, 21.02.2020 18:44 monkeys450

The planet Jupiter is more than 300 times as massive as Earth, so it might seem that a body on the surface of Jupiter would weigh 300 times as much as on Earth. But it so happens that a body would weigh scarcely 3 times as much on the surface of Jupiter as on the surface of Earth. Discuss why this is so, using the terms in the equation for gravitational force to guide your thinking.

Answers: 3

Show answers

Answers

Answer from: heartprague

See discussion below.

Explanation:

The weight of any body on the planet is the gravitational force of attraction between the planet and the body.

For Earth, Newton's law of gravitation expresses this force as

$F = G\dfrac{M_Em}{R_E^2}$

M_E is the mass of the Earth, is the mass of the body and R_E is the radius of the Earth which is the distance between the body and the Earth if it's on the Earth's surface. is the universal gravitational constant.

The weight of the body on Earth is

W=mg_E

Here, g_E is the gravitational acceleration on Earth.

Since both forces are equal,

$mg_E = G\dfrac{M_Em}{R_E^2}$

$g_E = G\dfrac{M_E}{R_E^2}$

It is seen that g_E depends only on the mass and radius of the Earth.

From the question, the mass of Jupiter is over 300 times that of the Earth. Let's name it M_J . Hence,

M_J=300M_E

If we denote Jupiter's gravitational acceleration with g_J and it's radius by R_J , then

$g_J = G\dfrac{M_J}{R_J^2}$

$g_J = G\dfrac{300M_E}{R_J^2}$

It would follow that this is 300 times as much that of earth. However, the radius of Jupiter is also much greater than the radius of the Earth. In fact, it is about 11 times greater i.e. R_J=11R_E .

Hence,

$g_J = G\dfrac{300M_E}{(11R_E)^2}$

$g_J = G\dfrac{300M_E}{121R_E^2}$

$g_J = \dfrac{300}{121}G\dfrac{M_E}{R_E^2}$

$g_J = 1.5G\dfrac{M_E}{R_E^2}$

g_J = 1.5g_E

It is thus seen that its gravity is only about 1.5 times that if the Earth. Hence, any object on Jupiter would only weigh 1.5 times as much as it would on Earth.

Answer from: khaz1430

Yes it is true that bodies only weigh 3 times more on Jupiter as they do on Earth. I will explain below.

Explanation:

By definition, weight is a product of mass and acceleration due to gravity, i.e

W = m * g

As we know from physics, mass is constant. So if the body's weight increases, it should be because g has changed on the different planet. Every planet has their acceleration due to gravity.

Now, from gravitational physics, acceleration due to gravity (g) is related to the gravitational constant (G) as follows:

$g = \frac{GM}{r^{2} }$

where M is mass and r is radius of planet.

So defining the weight of the body on both planets as $W_{J}$ and $W_{E}$ for Jupiter and Earth respectively.

The problem has stated that the ratio $\frac{W_{J}}{W_{E}}$ is roughly equal to 3. to confirm this, we use the above equations as follows:

$\frac{W_{J}}{W_{E}} = \frac{mg_{j} }{mg_{E}} =\frac{ \frac{GM_{J} }{r^{2}_{J} }}{\frac{GM_{E} }{r^{2}_{E} }}$

This gives

$\frac{W_{J}}{W_{E}} =\frac{M_{J}r^{2}_{E} }{M_{E}r^{2}_{J} }}$

As you must have seen from the question, Jupiter is 300 times heavier than Earth ( $\frac{M_{J} }{M_{E} }}$ =300 approximately), and by checking the radius of the Earth and Jupiter, which are respectively 6400km and 69000km roughly. So $\frac{r^{2}_{E} }{r^{2}_{J} }}$ is roughly 1/116. This means that

$\frac{W_{J}}{W_{E}}$ is approximately (300 * 1/120) = 2.59 or 3 approximately as claimed.

This means you would weigh 3 times as much on Jupiter as you weigh on Earth.

Answer from: Quest

$\frac{2y^2-5y-7}{6y^2+10y+4}-\frac{7}{9y^2+6y}=\frac{6y^2-21y-14}{6y\left(3y+2\right)}$

step-by-step explanation:

we are given

$\frac{2y^2-5y-7}{6y^2+10y+4}-\frac{7}{9y^2+6y}$

we have to simplify it

firstly, we will factor it

$2y^2-5y-7=\left(y+1\right)\left(2y-7\right)$

$6y^2+10y+4=2\left(y+1\right)\left(3y+2\right)$

$9y^2+6y=3y(3y+2)$

$=\frac{\left(y+1\right)\left(2y-7\right)}{2\left(y+1\right)\left(3y+2\right)}-\frac{7}{3y(3y+2)}$

now, we can cancel like terms

$=\frac{\left(2y-7\right)}{2\left(3y+2\right)}-\frac{7}{3y(3y+2)}$

now, we can combine it

$=\frac{3y(2y-7\right)}{6y\left(3y+2\right)}-\frac{7\times 2}{6y(3y+2)}$

$=\frac{3y(2y-7\right)-14}{6y\left(3y+2\right)}$

$=\frac{6y^2-21y-14}{6y\left(3y+2\right)}$

so, we get

$=\frac{6y^2-21y-14}{6y\left(3y+2\right)}$

Answer from: Quest

he made 11 calls in one day

Other questions on the subject: Physics

Physics, 22.06.2019 02:20, Hellokittyjam35

Which changes of state do the labels represent? a: b: c:

Answers: 1

continue

Physics, 22.06.2019 03:10, jazprincezz7606

Aphysical change is a change in the size, shape,, or stafe of matter true or false

Answers: 1

continue

Physics, 22.06.2019 05:10, zionnahl

Total solidification times of three casting geometries are to be compared: a sphere, a cylinder, in which the length-to-diameter ration - 1.0, and a cube. volume = 1000 cm^3 for all three shhapes, and the same casting alloy is used. a) determine the solidification times of each geometry b) based on the results of part (a), which geometric element would make the best riser? c) if the mold constant = 3.5 min/cm^2 in chvorinov's rule, compute the total solidification time for each casting.

Answers: 3

continue

Physics, 22.06.2019 06:30, jumpman2344

The coulomb's law explains which of the following? select all the force between two charged objects is inversely proportional to the charge on each object. the force between two charged objects is directly proportional to the charge on each object. the force between two charged objects is directly proportional to the distance separating them. the force between two charged objects is inversely proportional to the square of the distance separat coulomb's law is similar to newton's 2nd law. if the force between two objects is f and the charge on both objects is doubled, the new force between the would now be 2f. if the force between two objects is 2f and the distance separating them is doubled, the new force between the objects would now o the be zf.

Answers: 3

continue

You know the right answer?

The planet Jupiter is more than 300 times as massive as Earth, so it might seem that a body on the s...