Physics, 21.02.2020 05:23 Kelshonti15
A capacitor is charged to a potential of 12.0 V and is then connected to a voltmeter having an internal resistance of 3.90 MΩ. After a time of 3.50 s the voltmeter reads 3.5 V. After a time of 4.00 s the voltmeter reads 3.0 V. What are (a) the capacitance and (b) the time constant of the circuit?
Answers: 2
= 0.291
= ln (0.291)
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