A uniform electric field of magnitude 6.8 105 N/C points in the positive x-direction. Find the change in electric potential (?V) between the origin and each of the points given below.
(a) (0, 5.0 m)
V

(b) (5.0 m, 0)
V

(c) (5.0 m, 5.0 m)
V

Solution:

Substitute the values in the formula V=-E*d we get the answers

let us consider the electric field  that travels in a positive way or the positive direction and E denotes the magnitude

Where E= 6.8 10^5 N/C

We have the formula, V=-E*d

Take d value as 5 from the option  one

put V=0 since the fields are in the  X direction and the points are in the Y direction

By the formula,

(0, 5.0 m)

V=-E*d

V= -6.8x10^5V/m*5m

V=-3.40x10^6V

By the formula (5.0 m, 0)

V=-E*d

V= -6.8x10^5V/m*5m

V=-3.40x10^6V

By the formula ,

(5.0 m, 5.0 m)

V=-E*d

V= -6.8x10^5V/m*5m

V=-3.40x10^6V

sub V=5 we get,

V=-3.40x10^6V+5

v=2.40x10^6V

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the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)